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3x^2+35x-304=0
a = 3; b = 35; c = -304;
Δ = b2-4ac
Δ = 352-4·3·(-304)
Δ = 4873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{4873}}{2*3}=\frac{-35-\sqrt{4873}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{4873}}{2*3}=\frac{-35+\sqrt{4873}}{6} $
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